http://gcc.gnu.org/bugzilla/show_bug.cgi?id=55766
Bug #: 55766 Summary: temlate alias is not equivalent (const-ness is not recognized) Classification: Unclassified Product: gcc Version: 4.8.0 Status: UNCONFIRMED Severity: normal Priority: P3 Component: c++ AssignedTo: unassig...@gcc.gnu.org ReportedBy: leo...@volnitsky.com Created attachment 29016 --> http://gcc.gnu.org/bugzilla/attachment.cgi?id=29016 goog.ii I have following alias in my code: template<bool Cnd, class T=void> using eIF = typename std::enable_if <Cnd,T>::type; I encountered code where alias is not equivalent to direct use of enable_if. Attached are good.ii (with enable_if) which both GCC480-20121220 and CLANG32 can compile, and bad.ii (with alias eIF), which only CLANG can compile. diff good.ii bad.ii 80517c80517 < typename std::enable_if<(sizeof(Arg1),N==1), Arg1>::type --- > eIF<(sizeof(Arg1),N==1), Arg1> 80522c80522 < typename std::enable_if<(sizeof(Arg1),N==2), Arg2>::type --- > eIF<(sizeof(Arg1), N==2), Arg2> Comma op in expression (sizeof(Arg1),N==1) used to makes templated member function depend on Arg1 template argument (to trigger SFINAE). Error message: lambda.h:45:2: error: integral expression ‘(0, false)’ is not constant