http://gcc.gnu.org/bugzilla/show_bug.cgi?id=51652
Bug #: 51652
Summary: [F03] ICE with allocatable scalars
Classification: Unclassified
Product: gcc
Version: 4.7.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: fortran
AssignedTo: unassig...@gcc.gnu.org
ReportedBy: davidgkinnibu...@yahoo.co.uk
module settings
type keyword
! character(60), allocatable :: c(:) ! works but should it?
! character(80), allocatable :: c(:) ! works
character(:), allocatable :: c(:)
end type keyword
type(keyword) :: kw(10)
contains
subroutine save_kw
!allocate(kw(1)%c(10))
allocate(character(80) :: kw(1)%c(10))
kw(1)%c(1) = 'abcd'
if (kw(1)%c(1).eq.'abcd') then ! problem here
print *, 'yes'
else
print *, 'no'
endif
end subroutine save_kw
end module settings
!*************************************************************************
program ice
use settings
call save_kw
end program ice
gcc version 4.7.0 20111212 (experimental) [trunk revision 182257] (GCC)
=========================================================================
f951.exe: internal compiler error: in gfc_get_derived_type, at
fortran/trans-types.c:2401
I'm also interested in testing substrings like
if (kw(1)%c(1)(1:1).eq.'a') then ...
The above program works ok with non-deferred scalar lengths. However, it also
works when the component is assigned different lengths in the subroutine and
main body (e.g. 60 and 80) whereas Intel Fortran reports this as an error: "In
an ALLOCATE statement the type parameter values in type specification must be
the same as a corresponding nondeferred values of the objects being
allocated.".
