http://gcc.gnu.org/bugzilla/show_bug.cgi?id=51294
--- Comment #2 from Jonathan Wakely <redi at gcc dot gnu.org> 2011-11-24 12:01:49 UTC --- (In reply to comment #0) > 0 is a const so the compiler should be able to choose the correct type. 0 is an int, so the compiler is required by the standard to make the conditional expression (haveBar?bar_:0) have type int. It shouldn't warn though, as the conversion from int to char won't alter the value. > The workaround is either to disable the warning with -Wno-conversion or add > unecessary constants as below. I don't think this is acceptable. Or (haveBar?bar_:(char)0)
