http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49934
Summary: gcc 4.6.1 messes up code Product: gcc Version: unknown Status: UNCONFIRMED Severity: normal Priority: P3 Component: c AssignedTo: unassig...@gcc.gnu.org ReportedBy: andy_c...@mailup.net here is the original function void keypad_isr(void) { /* read a character from the key buffer */ FPGA_UART_DATA *ptr; /* volatile register makes no dif */ FPGA_UART_DATA kpd; int g; int n; KEYBUFFER *kb; char ch; kb = &key_buffer; asm(" halt"); /* just for debugging */ ptr = FPGA_UART; /* make a pointer to the FPGA register */ // read upto 8 keys from the keypad for( n = 0; n < 8 ; n++ ) { kpd = *ptr; /* read from register (only do this ONCE) */ g = kpd.fifo_cnt; if(g == 0) return; ch = (char) kpd.rx_data; kb->status = ch; if( ch != 0 && ch != -1 ) { if ( kb->current_location >= MAX_KEY_BUFFERS_SIZE-1 ) { kb->current_location = MAX_KEY_BUFFERS_SIZE-1; } kb->key_buff[kb->current_location] = ch; kb->current_location++; } } } ok now here is my problem, gcc does not use an address register for the pointer, and it insists on reading the FPGA directly twice ???? here is generated assembly from gcc. dat's not wot I rit... keypad_isr: lea (-12,%sp),%sp movem.l #1036,(%sp) move.w -1073741664,%d0 clr.l %d1 move.w %d0,%d1 moveq #13,%d2 lsr.l %d2,%d1 tst.b %d1 jeq .L3 moveq #8,%d1 lea key_buffer+33,%a1 lea key_buffer,%a0 lea key_buffer+1,%a2 jra .L5 .L8: move.w -1073741664,%d0 <<< --- look its done it again ????? clr.l %d2 move.w %d0,%d2 <<< --- ARRRGGGgg its knackered my FPGA moveq #13,%d3 lsr.l %d3,%d2 tst.b %d2 jeq .L3 .L5: move.b %d0,%d2 move.b %d0,(%a1) move.l %d2,%d0 addq.l #1,%d0 and.l #255,%d0 moveq #1,%d3 cmp.l %d0,%d3 jcc .L6 clr.l %d0 move.b (%a0),%d0 move.b #30,%d3 cmp.l %d0,%d3 jcc .L7 move.b #31,(%a0) .L7: move.b (%a0),%d0 clr.l %d3 move.b %d0,%d3 move.b %d2,(%a2,%d3.l) addq.l #1,%d0 move.b %d0,(%a0) .L6: subq.l #1,%d1 jne .L8 .L3: movem.l (%sp),#1036 lea (12,%sp),%sp rts