------- Comment #20 from dominiq at lps dot ens dot fr  2010-04-14 13:06 -------
I have been able to get the following values before the crash:

DEBav = 

0.59252398402327489       1.58848116996742547E-002  2.31157896165751706E-002  
8.33002598145726886E-002  9.03564427292446321E-002  -596152.33325048804       
-173.27129371256277        284192.62549692224       -226.34926169938268       
-2145.2785283028134        6880.2385948782830        25825.135912393274        
26997.892028831531                            NaN   0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000

XA = 

0.0000000000000000        1.0000000000000000        1.0000000000000000        
1.0000000000000000        1.0000000000000000        1.0000000000000000        
1.0000000000000000       0.99999999999999989        1.0000000000000000        
1.0000000000000000        1.0000000000000000       0.49470835610659347       
                    NaN                       NaN   0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000  

XB =

0.0000000000000000        0.0000000000000000       4.95714580495132420E-018   
0.0000000000000000        0.0000000000000000        0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000        
0.0000000000000000        0.0000000000000000       7.34677397984116187E-002   
                    NaN                       NaN   0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000        
0.0000000000000000        0.0000000000000000        0.0000000000000000

ie = I - 1
debe = DEBav(ie)
debs = DEBav(I)
deve = XA(ie)*debe + XB(ie)
devs = XA(I)*debs + XB(I)
sec = SCApa(I)
debm = (deve+devs)/2.D+00
eps = 1.D+00
IF ( debm.LT.0. ) eps = -1.D+00
vis = (r+s*tf)/3600.D+00
Re = eps*debm*DIAhy/(vis*sec)

So if I= 13, 14, or 15, Re is a NaN.


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=43716

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