The attached program gives a warning about 'check_moo' being unused,
despite the variable being declared with __attribute__ ((__unused__)).
================================= bug.cc ==================================
extern "C" int c_foo (void);
namespace gnulib { static int (*foo) (void) = ::c_foo; }
static int (* __attribute__ ((__unused__)) check_foo) (void) = gnulib::foo;
extern "C" int c_moo (void);
namespace gnulib { static int (*const moo) (void) = ::c_moo; }
static int (* __attribute__ ((__unused__)) check_moo) (void) = gnulib::moo;
===========================================================================
$ g++ -Wall -S bug.cc
bug.cc:7: warning: 'check_moo' defined but not used
The warning is present in all g++ version of 3.x and 4.x that I tested,
except in g++ 4.0.2. I.e. "Known to work" = 4.0.2, "Known to fail" =
4.0.4, 4.1.2, 4.2.4, 4.3.4, 4.4.3.
The only difference between check_foo (which does not elicit a warning)
and check_moo is the 'const'ness of the initializer.
--
Summary: warning with -Wall despite __attribute__ ((__unused__))
Product: gcc
Version: 4.4.3
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: bruno at clisp dot org
GCC build triplet: i686-pc-linux-gnu
GCC host triplet: i686-pc-linux-gnu
GCC target triplet: i686-pc-linux-gnu
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=43454
