Stock RHEL5 g++ 4.4 version:
[Mon Mar 15 17:04:26] kenny:~/work$g++44 -v
Using built-in specs.
Target: i386-redhat-linux6E
Configured with: ../configure --prefix=/usr --mandir=/usr/share/man
--infodir=/usr/share/info --with-bugurl=http://bugzilla.redhat.com/bugzilla
--enable-bootstrap --enable-shared --enable-threads=posix
--enable-checking=release --with-system-zlib --enable-__cxa_atexit
--disable-libunwind-exceptions --enable-languages=c,c++,fortran
--disable-libgcj
--with-mpfr=/builddir/build/BUILD/gcc-4.4.0-20090514/obj-i386-redhat-linux6E/mpfr-install/
--with-ppl=/builddir/build/BUILD/gcc-4.4.0-20090514/obj-i386-redhat-linux6E/ppl-install
--with-cloog=/builddir/build/BUILD/gcc-4.4.0-20090514/obj-i386-redhat-linux6E/cloog-install
--with-tune=generic --with-arch=i586 --build=i386-redhat-linux6E
Thread model: posix
gcc version 4.4.0 20090514 (Red Hat 4.4.0-6) (GCC)
Assume that there is a C++ shared library that uses STL extensively and is
compiled with -fvisibility-ms-compat. Template member instantiations are
however still visible:
[Mon Mar 15 17:18:00] kenny:~/work$g++44 -c -fvisibility-ms-compat vis2.cc
[Mon Mar 15 17:18:03] kenny:~/work$readelf -sW vis2.o | grep foo
153: 00000000 207 FUNC GLOBAL DEFAULT 72 _Z3foov
ok, we want "foo" to be visible outside our shared library, but we do not want
the following symbol to be visible:
[Mon Mar 15 17:18:07] kenny:~/work$readelf -sW vis2.o | grep _M_range
179: 00000000 505 FUNC WEAK DEFAULT 121
_ZNSt5dequeIiSaIiEE19_M_range_initializeISt15_Deque_iteratorIiRiPiEEEvT_S7_St20forward_iterator_tag
vis2.cc source code is:
--- cut vis2.cc ---
#include <deque>
#define FOO_EXPORT __attribute__((visibility("default")))
int FOO_EXPORT
foo()
{
std::deque<int> a;
std::deque<int> b(a.begin(), a.end());
return 0;
}
--- cut vis2.cc ---
This can be considered as an STL bug ("std" namespace is declared as having
default visibility and thus all classes and all their members have default
visibility) -- one may set "hidden" visibility on template member functions.
But I think that at least -fvisibility-ms-compat should produce the code when
template instantiations have hidden visibility, otherwise it will not be
possible to be source-compatible with Visual Studio on this matter. I mean that
the following source code (being an example of source compatibility with Visual
Studio wrt. hidden visibility) will be compiled differently if used in shared
library (or .DLL):
--- cut foo.h ---
#include <iostream>
#if defined(_MSC_VER)
#define FOO_EXPORT __declspec(dllexport)
#define FOO_IMPORT __declspec(dllimport)
#else
#define FOO_EXPORT __attribute__((visibility("default")))
#define FOO_IMPORT __attribute__((visibility("default")))
#endif
#if defined(_BUILD_FOO_DLL)
#define FOO_API FOO_EXPORT
#else
#define FOO_API FOO_IMPORT
#endif
class FOO_API Foo
{
public:
template<typename T>
void foo(const T &t) {
std::cout << t << std::endl;
}
};
--- cut foo.h ---
Or there should be additional command line option that enables such behavior.
--
Summary: template member function instantiations are not hidden
if the class has default visibility and -fvisibility-ms-
compat is used
Product: gcc
Version: unknown
Status: UNCONFIRMED
Severity: major
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: fjoe at samodelkin dot net
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=43376
