------- Comment #2 from igodard at pacbell dot net 2009-08-13 02:47 ------- Well, if the call is on foo then surely a foo can call; its own methods, whereas if the call is on bar then a bar should see the protected methods of its base class foo. Either way it should be visible.
-- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41050
