------- Comment #1 from jakub at gcc dot gnu dot org 2009-06-17 08:04 -------
That's undefined behavior, there is no sequence point between the the
evaluation of foo (&n, n) and evaluation of n passed as the next argument.
If foo (&n, n) is evaluated first, you will see 1 2 printed, if n is evaluated
first, you see 1 1.
--
jakub at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=40471
