This code:
struct B1 {
void f(int*);
};
struct B2 {
void f(double*);
};
struct D: B1, B2 {
private:
using B1::f;
using B2::f;
};
template <typename T>
struct B
{
public:
void f(T arg);
};
template <typename T, typename U>
struct DD: B<T>, B<U>
{
private:
using B<T>::f;
using B<U>::f;
};
int main()
{
D d;
d.f((int*)0);
DD<int*, double*> dd;
dd.f((int*)0);
}
Has the following error when compiling:
$ g++-4.3 -pedantic-errors -Wall -Wextra usingdecl.cpp
usingdecl.cpp: In function int main():
usingdecl.cpp:2: error: void B1::f(int*) is inaccessible
usingdecl.cpp:34: error: within this context
I thing there should be the same error line 36 (for the call to dd.f).
About versions: g++ 3.3 doesn't give any error. 3.4 and 4.0 gives both. The
reported state is the behaviour since 4.1.
--
Summary: using declaration doesn't control accessibility in
template
Product: gcc
Version: 4.3.1
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: jm at bourguet dot org
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38962
