------- Comment #1 from dfranke at gcc dot gnu dot org  2008-12-22 15:16 -------
The same holds if G is an external subroutine and the module provides an
explicit interface, but not, if the interface is defined in F (errors out).

SUBROUTINE g()
  print *, 'external'
END SUBROUTINE

MODULE m
INTERFACE
  SUBROUTINE g()
  END SUBROUTINE
END INTERFACE
CONTAINS
  SUBROUTINE f()
    CALL g()
  CONTAINS
    SUBROUTINE g()
      print *, 'contained'
    END SUBROUTINE
  END SUBROUTINE
END MODULE

use m
call g()
call f()
call g()
end


-- 


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=38594

Reply via email to