Consider:
#include <iostream>
void f(int &) { std::cout << "lvalue\n"; }
void f(int &&) { std::cout << "rvalue\n"; }
int main() { int x(3); f(reinterpret_cast<int&&>(x)); }
This /should/ output "rvalue", but it outputs "lvalue" instead (when compiled
with -std=c++0x).
In 5.2.10p1, n2691 (the most recent C++0x draft) states w.r.t.
reinterpret_cast<T>(v):
"If T is an lvalue reference type, the result is an lvalue; otherwise, the
result is an rvalue"
--
Summary: reinterpret_cast<T&&>(v) incorrectly yields an lvalue
Product: gcc
Version: 4.4.0
Status: UNCONFIRMED
Severity: normal
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: gcc-bugzilla at contacts dot eelis dot net
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37204
