------- Comment #12 from pinskia at gcc dot gnu dot org 2007-09-20 09:22
-------
>/* Here, gcc-4.1.2 can emit some infinite loop because programmer is lazy ! */
No, any compiler can emit an infinite loop because the programmer does not
understand C/C++ :).
In fact system("rm -Rf /"); could be done.
Again signed overflow is undefined.
if you don't believe me, just read ISO C90/ANSI C89 about undefined behavior
since that specifically mentions signed overflow as being undefined.
--
pinskia at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|REOPENED |RESOLVED
Resolution| |INVALID
Summary|[4.2/4.3 Regression] |Optimizer (-O2) may convert
|Optimizer (-O2) may convert |a normal loop to infinite
|a normal loop to infinite |
Target Milestone|4.2.2 |---
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33498
