------- Comment #1 from pinskia at gcc dot gnu dot org  2007-09-18 11:00 -------
No, "B" is correct.


        A &Aref = Binst;
        Aref = Cinst;

is the same as:
Binst = (A)Cinst;


-- 

pinskia at gcc dot gnu dot org changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |INVALID


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33470

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