------- Comment #1 from pinskia at gcc dot gnu dot org 2007-09-18 11:00 ------- No, "B" is correct.
A &Aref = Binst; Aref = Cinst; is the same as: Binst = (A)Cinst; -- pinskia at gcc dot gnu dot org changed: What |Removed |Added ---------------------------------------------------------------------------- Status|UNCONFIRMED |RESOLVED Resolution| |INVALID http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33470