------- Comment #1 from pinskia at gcc dot gnu dot org 2007-08-23 19:00 ------- No, this is correct, f in B hides all of f's in A, no matter what argument types of f are in A. You have to add "using A::f;" inside B to get the behavior you want.
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pinskia at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33165
