On 8/21/07, Michael Williamson <[EMAIL PROTECTED]> wrote: > I would expect a message like: > > "the second parameter is not a pointer".
Because '\0' can converted to a pointer type as it is a 0 (for a NULL pointer). -- Pinski
On 8/21/07, Michael Williamson <[EMAIL PROTECTED]> wrote: > I would expect a message like: > > "the second parameter is not a pointer".
Because '\0' can converted to a pointer type as it is a 0 (for a NULL pointer). -- Pinski