------- Comment #1 from pinskia at gcc dot gnu dot org 2007-08-06 04:56 -------
If I add a check for errors:
#include <iostream>
using namespace std;
int main() {
cout
<< "Input in hex two integers x and y." << endl;
int x, y;
if(!cin)
cout << "error" << endl;
cin >> hex >> x >> y;
if(!cin)
cout << "error" << endl;
else
cout << "y: " << y << "x: " << x << endl;
}
----
Then I get this behavior:
Input in hex two integers x and y.
aaaaaaaa
error
If I enter less than 8 digits, it gets accepted.
--
pinskia at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Component|c++ |libstdc++
GCC build triplet|gcc version 3.4.6 20060404 |
|(Red Hat 3.4.6-3) |
GCC host triplet|linux.cs.uvic.ca |
GCC target triplet|linux.cs.uvic.ca |
Summary|cin fails to allow input to |cin and hex input (==8
|be entered |digits gets rejected)
Version|unknown |3.4.6
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=33000
