When calling a procedure with signed char or short arguments using -sizeof() as
an expression, an "<filename>:<line#>: warning: overflow in implicit constant
conversion" is output. Arguments with int or long do not. This happens even
though there is no real overflow (e.g. if -sizeof() evaluates to -4). See
attached test program (compiled using command line m68k-elf-g++ -c
testcpp.cpp). Proper code is produced. Warning can be avoided by casting
sizeof() to int (i.e. -(int)sizeof() ). Similar results are obtained when
returning a -sizeof() value in procedures with return type signed char or
short. This warning does not occur in revision 3.4.6.
--
Summary: inconsistant overflow in implicit conversion warning
with -sizeof()
Product: gcc
Version: 4.2.0
Status: UNCONFIRMED
Severity: trivial
Priority: P3
Component: c++
AssignedTo: unassigned at gcc dot gnu dot org
ReportedBy: Steve at Zook dot com
GCC host triplet: i386-pc-cygwin
GCC target triplet: m68k-elf-unknown
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=32782
