------- Comment #4 from pinskia at gcc dot gnu dot org 2007-03-20 05:54 -------
Closing again, this time as won't fix. Fortran is not C/C++/Java. This case
if you get -fbounds-check failing, then the bug is in the code and not in
Gfortran. Yes the standard might allow for short circuiting but it does not
disallow for not short circuiting. Also the code is depning on the current
behavior of Gfortran which might change in the future. -fbounds-check just
shows this case is undefined.
--
pinskia at gcc dot gnu dot org changed:
What |Removed |Added
----------------------------------------------------------------------------
Status|NEW |RESOLVED
Resolution| |WONTFIX
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=31269
