------- Additional Comments From pinskia at gcc dot gnu dot org 2005-09-16
03:36 -------
(In reply to comment #2)
> No idea why that is. What's the logic behind this? Make my code twice as
> long?
The standard says this, did you read the page I gave? If not then I copied and
pasted what is relevant to
your issue:
In a template definition, unqualified names will no longer find members of a
dependent base (as
specified by [temp.dep]/3 in the C++ standard). For example,
template <typename T> struct B {
int m;
int n;
int f ();
int g ();
};
int n;
int g ();
template <typename T> struct C : B<T> {
void h ()
{
m = 0; // error
f (); // error
n = 0; // ::n is modified
g (); // ::g is called
}
};
You must make the names dependent, e.g. by prefixing them with this->. Here is
the corrected
definition of C<T>::h,
template <typename T> void C<T>::h ()
{
this->m = 0;
this->f ();
this->n = 0
this->g ();
}
As an alternative solution (unfortunately not backwards compatible with GCC
3.3), you may use using
declarations instead of this->:
template <typename T> struct C : B<T> {
using B<T>::m;
using B<T>::f;
using B<T>::n;
using B<T>::g;
void h ()
{
m = 0;
f ();
n = 0;
g ();
}
};
--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=23908
