------- Additional Comments From bangerth at dealii dot org 2005-07-23 21:15
-------
No, the standard says that the result for an iterator 'i' in the output
range is
((...(*first + *(first + 1)) + ...) + *(first + (i - result)))
So arithmetic is done with the data type of the input range. That may be
undesirable on occasion, but that's what the standard says.
W.
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=22634
