------- Additional Comments From bangerth at dealii dot org 2005-07-23 20:56
-------
You can't specialize an inner template without specializing its outer
template as well.
As per /18:
18In an explicit specialization declaration for a member of a class
template or a member template that appears in namespace scope, the
member template and some of its enclosing class templates may remain
unspecialized, except that the declaration shall not explicitly
specialize a class member template if its enclosing class templates
are not explicitly specialized as well. In such explicit
specialization declaration, the keyword template followed by a
template-parameter-list shall be provided instead of the template<>
preceding the explicit specialization declaration of the member. The
types of the template-parameters in the template-parameter-list shall
be the same as those specified in the primary template definition.
[Example:
template<class T1> class A {
template<class T2> class B {
template<class T3> void mf1(T3);
void mf2();
};
};
template<> template<class X>
class A<int>::B { };
template<> template<> template<class T>
void A<int>::B<double>::mf1(T t) { }
template<class Y> template<>
void A<Y>::B<double>::mf2() { } // ill-formed; B<double> is
specialized but
// its enclosing class template A is
not
--end example]
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=22114
