------- Additional Comments From squell at alumina dot nl 2005-07-23 16:26
-------
(In reply to comment #6)
> In your example, ptr is a type not an object. operator-> isn't applicable
> to types, only to objects.
ptr _is_ an object. Please re-read the declaration carefully. All gcc versions
(correctly) allow this (in the reduced case):
int (*fp)() = ptr->f;
But in this case, the initialized expression isn't required to be a
constant address expression. I think my claim that g++ rejected my
original code because it rejects '->' in a constant expression is correct.
The original issue should probably be downgraded in its severity. It is too
obscure and there is a work-around.
However, if "&obj->staticmember" is a constant address expression, then G++
should not reject it. If it is not, this is a defect in C++, not GCC.
--
What |Removed |Added
----------------------------------------------------------------------------
Severity|normal |minor
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=22621
