------- Additional Comments From gcc2eran at tromer dot org 2005-07-08 09:18 ------- (In reply to comment #13) > In the C99 standard, 6.5.4 Cast Operators, Footnote 85 "A cast does not > yield an lvalue. Thus, a cast to a qualified type has the same effect > as a cast to the unqualified version of the type."
But the object being accessed is the one designated by *dereferencing* the cast expression, and *that* is an lvalue. Quoting N1124: "[6.5.3.2/4] The unary * operator denotes indirection. If the operand [...] points to an object, the result is an lvalue designating the object. If the operand has type pointer to type, the result has type type." And of course: "[6.5.4/2] Preceding an expression by a parenthesized type name converts the value of the expression to the named type. [...]" I think this answers the first half of your quote (i.e., footnote 86), but I'm not sure what to make of the second half, especially in light of the "Thus". -- http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21568
