------- Additional Comments From bangerth at dealii dot org 2005-05-12 17:49
-------
You can't do this:
template<typename T>
std::ostream & std::operator<< (std::ostream &, a::A<T> const &);
If you want to overload something in namespace std, you have to open that
namespace, put the declaration in it, and close it again. If you do this
everything is fine, i.e. like so:
namespace std
{
template<typename T>
ostream & operator<< (ostream &, a::A<T> const &);
}
The fact that we don't reject the declaration is a bug in gcc in itself,
for which I'll open a PR in a minute.
W.
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21515
