------- Additional Comments From giovannibajo at libero dot it 2005-03-04
07:35 -------
To tell you the truth, a template is not a type. A template specialization (as
in: foo<int>) is a type, but not a template. So, this is correct. The error
happens because "foo" does not name a type and thus P cannot be deduced.
--
What |Removed |Added
----------------------------------------------------------------------------
Status|UNCONFIRMED |RESOLVED
Resolution| |INVALID
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=20311
