You're right. Print is not the problem. Another part of Gambas could
raise an error. But Benoit is right. Doing this kind of check is too
resource intensive. You're also right. Since DateDiff(gb.second) will
overflow for a ~70 year difference, over the longer term, it should
return a long. Since this kind of edge case is rare, it's not an urgent
change and,in fact, may cause problems for existing code.
On 2017-08-06 02:27 PM, d4t4f...@gmail.com wrote:
Toni,
I don't think Print is at fault here at all. My guess is that DateDiff may need an
"attitude adjustment" in these cases: It may need to either raise an overflow
error or return a 64bit Long.
Hope this helps,
zxMarce.
On Aug 6, 2017, 12:00, at 12:00, Tony Morehen <tmore...@ajmconsulting.ca> wrote:
zxMarce, you are exactly right. DateDiff returns an integer so when
print adds the two datediff it adds 2 signed integers and gets an
signed
integer. Since the max value of a signed integer is 2147483647, the
answer of 2208988800 overflows to -2085978496. So print's behaviour is
as expected. The only question is: Should print raise an overflow
error? Note that there has not been a hardware overflow so the
gambas's
math engine must do the overflow check (by matching signs).
On 2017-08-06 10:30 AM, d4t4f...@gmail.com wrote:
Without a machine nearby, I'd risk you're in the right track.
The DIM AS LONG creates 64bit vars while DateDiff may return 32bit
data (don't have the docs with me).
Print will use 64bit to print the vars and 32bit with direct DateDiff
(you may confirm by using CLng to affect the DateDiff's in the second
Print)
Remember that when you have the most significant bit (MSB) set,
Gambas will interpret the value as twos-complement sign and yield
negative values.
Regards,
zxMarce.
On Aug 6, 2017, 10:21, at 10:21, Hans Lehmann <h...@gambas-buch.de>
wrote:
Hello,
Why are two different results:
Public Sub Main()
Dim a, b As Long
a = DateDiff("01/01/1900", "01/01/1935", gb.Second)
b = DateDiff("01/01/1935", "01/01/1970 ", gb.Second)
Print a + b
Print DateDiff("01/01/1900", "01/01/1935", gb.Second) +
DateDiff("01/01/1935", "01/01/1970 ", gb.Second)
End
Results:
2208988800 ' ok
-2085978496 ' complement?
Best regards
Hans
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