A variant of the previous suggestions, to ignored (5) voids :-)
Public Sub Main()
Dim ss As String[]
Dim s As String
ss = Split("hello#####12345", "#")
For Each s In ss
If Not IsNull(s) Then Print s;
Next
End
Regards
Gianluigi
2017-05-23 8:38 GMT+02:00 Fabien Bodard <gambas...@gmail.com>:
> A=Split (replace ("gggg##yyy##1234","##",chr (27)),chr (27))
>
> Or do not use double characters as separator .
>
>
>
>
> Le 22 mai 2017 23:35, <d4t4f...@gmail.com> a écrit :
>
> > Matti
> >
> > Your string has 3 substrings when split with SPLIT (STRING, "#"):
> >
> > Index 0: "Hello"
> > Index 1: ""
> > Index 2: "12345"
> >
> > It is documented that separators are single characters, not strings; you
> > can specify a string because any of its individual characters may be used
> > as separator.
> >
> > If you also specify IgnoreVoids as True, split should omit the null
> string
> > and return only:
> >
> > Index 0: "Hello"
> > Index 1: "12345"
> >
> > HTH,
> > zxMarce.
> >
> > On May 22, 2017, 18:02, at 18:02, Matti <matti.e...@vodafone.de> wrote:
> > >Ok, thank you, Tobi.
> > >I'll have to start thinking again (but not tonight anymore).
> > >Matti
> > >
> > >Am 22.05.2017 um 22:17 schrieb Tobias Boege:
> > >> On Mon, 22 May 2017, Matti wrote:
> > >>> If I have a string sStr="hello##12345" and want to split it:
> > >>>
> > >>> Dim aSplit as String[]
> > >>> aSplit = Split(sStr, "##")
> > >>> Print aSplit[0], aSplit[1]
> > >>>
> > >>> Returns always only "hello". Maybe "12345" is excluded because being
> > >an integer?
> > >>>
> > >> It is not an integer in this case. It's a string of characters and
> > >Split()
> > >> doesn't interpret it as an integer. Consequently it has nothing to do
> > >with
> > >> IgnoreVoid in my book.
> > >>
> > >> If anything is wrong, it is your use of the separator. According to
> > >the
> > >> documentation (and the implementation!), the Separator argument is a
> > >*list*
> > >> of separator characters, i.e. "##" will not split against the string
> > >"##",
> > >> but it will split against "#" or "#".
> > >>
> > >> To give a different example, if you had given the string
> > >"abc#123,456" and
> > >> separators "#," you would have gotten the array ["abc", "123",
> > >"456"].
> > >>
> > >>> Now the Wiki says "StringArray = Split ( String [ , Separators ,
> > >Escape , IgnoreVoid , KeepEscape ] )"
> > >>> Where "IgnoreVoid" means "a boolean that tells Split() *not* to
> > >return void elements."
> > >>>
> > >>> By trial and error I found out that "IgnoreVoid" has to be set to
> > >'True' to return "12345". Exactly the opposite.
> > >>>
> > >>> The Wiki should be corrected here.
> > >>>
> > >> I don't know what's the problem with your installation but on mine I
> > >get:
> > >>
> > >> $ gbx3 -e 'Split("hello##12345", "##").Join("|")'
> > >> hello||12345
> > >>
> > >> i.e. it works. Notice the empty string between "hello" and "12345"
> > >> in the context of what I explained about the separators above!
> > >>
> > >> Regards,
> > >> Tobi
> > >>
> > >
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