maybe with gb.pcre : regexp or Public Function CountChar(sValue as string, sChar as string) as integer dim i, iRet as integer
for i =1 to len (sValue)+1 if mid(sValue,i,1)=sChar then inc iRet next return iRet end print CountChar("coucou ça va ?", "a") $ 2 Or a super version thet remember a position: Public Function GetCharPos(sValue as string, sChar as string) as integer[] dim i as integer dim aRet as new integer[] for i =1 to len (sValue)+1 if mid(sValue,i,1)=sChar then aRet.add(i) next return aRet end print GetCharPos("Hello how are you", "e").Count 2011/11/11 Rolf-Werner Eilert <eilert-sprac...@t-online.de>: > Hi all, > > just a short question: Is there a function which simply counts how many > times a character appears within a string? I vaguely remember a long > time ago I used such a thing, but it may as well have been in another > context. > > The only way I have found yet was using Split() and then count the > number of resulting parts -1 IF it is more than 0. > > Any better way? > > Rolf > > ------------------------------------------------------------------------------ > RSA(R) Conference 2012 > Save $700 by Nov 18 > Register now > http://p.sf.net/sfu/rsa-sfdev2dev1 > _______________________________________________ > Gambas-user mailing list > Gambas-user@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/gambas-user > -- Fabien Bodard ------------------------------------------------------------------------------ RSA(R) Conference 2012 Save $700 by Nov 18 Register now http://p.sf.net/sfu/rsa-sfdev2dev1 _______________________________________________ Gambas-user mailing list Gambas-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/gambas-user