> According to some previous answers to my questions about performing > arithmetic operations on dates and times, the fractional part of a date > (cfloat[now] - fix[cfloat(now)]) represents the time of day and the > integer part (fix[cfloat(now)]) represents the number of days elapsed > since the beginning of time. > > So if it's 12:00 PM then cfloat(now) should display x.5, meaning half > the day has passed. > > If I enter ?cfloat(now) in the immediate window I get something like > 2487839.71017654 even though it's 10:02 PM. If x.0 is midnight, x.5 is > noon, etc., how is x.7 10:00 PM? Shouldn't 10:00 PM be something closer > to x.916666674? > > I thought at first it was because I was scaling time, but the immediate > window proved that wrong (immediately!). Any insight appreciated as always.
Date/time values are internally stored in GMT time. Regards, -- Benoît Minisini ------------------------------------------------------------------------------ Simplify data backup and recovery for your virtual environment with vRanger. Installation's a snap, and flexible recovery options mean your data is safe, secure and there when you need it. Data protection magic? Nope - It's vRanger. Get your free trial download today. http://p.sf.net/sfu/quest-sfdev2dev _______________________________________________ Gambas-user mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/gambas-user
