Bastien Semene
Administrateur Réseau& Système
Cyanide Studio - FRANCE
Le 20/04/2011 15:01, Ruben de Groot a écrit :
On Tue, Apr 19, 2011 at 04:00:52PM +0200, Bastien Semene typed:
Hi list,
I have a cron task set up using lockf.
I'd like to redirect one exit status to /dev/null :
"it (lockf command) returns one of the exit codes defined in
sysexits(3), as follows:
EX_TEMPFAIL The specified lock file was already locked by another
process.
EX_CANTCREAT The lockf utility was unable to create the lock
file, e.g.,
because of insufficient access privileges.
EX_USAGE There was an error on the lockf command line.
EX_OSERR A system call (e.g., fork(2)) failed unexpectedly.
EX_SOFTWARE The command did not exit normally, but may have been
sig-
naled or stopped."
I don't care about the EX_TEMPFAIL output as I consider it as a
successful exit status, not an error.
I there a trick to do that in a short way ?
something like
logfile=/var/log/lockf.log
lockf lockfile command
[ $? -eq 75 ]&& logfile=/dev/null ## EX_TEMPFAIL is defined to be 75
Ruben
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I used this $? test in a script.
My question was to know if it is possible to do this in 1 command line,
but I found nothing anywhere to do this.
Thank you for the answer !
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