> struct foo *fee; > > It's possible that: > > sizeof(struct foo) != (((char *)&fee[1]) - ((char *)&fee[0])) > > because of end-padding, which is not accounted for in arrays,
Er, no, that's not right. Otherwise fee = malloc(n * sizeof(struct foo)) wouldn't work. C89 says: There may also be unnamed padding at the end of a structure or union, as necessary to achieve the proper alignment were the structure or union to be an element of an array. And: the result [of sizeof] is the total number of bytes in such an object, including internal and trailing padding. So if a struct needs padding in an array, it has it even when it isn't in an array. -- Richard To Unsubscribe: send mail to [EMAIL PROTECTED] with "unsubscribe freebsd-current" in the body of the message
