On Sun, Nov 15, 2020 at 1:33 PM Guy Yur <guy...@gmail.com> wrote:
>
> On 15/11/20 8:55 pm, Scott Long wrote:
> > This is fixed in revision 367701
> >
> > Scott
>
> Hi,
>
> I am on revision 367710 (newer) and have the same problem.
> sysctlbyname() returns an empty string and length of 1.
> sysctl() with name converted to mib works fine.
>
> ssize_t tmplen;
> char path[1000] = { 0 };
>
> tmplen = getlocalbase(path, sizeof(path));
> printf("%s : %zd\n", path, tmplen);
>
> tmplen = sizeof(path);
> if (sysctlbyname("user.localbase", path, (size_t *)&tmplen, NULL, 0) == 0)
> printf("%s : %zd\n", path, tmplen);
>
> int mib[100] = { 0 };
> size_t miblen;
> if (sysctlnametomib("user.localbase", mib, &miblen) == 0) {
> for (int i = 0; i < miblen; i++)
> printf("%d ", mib[i]);
> printf("\n");
> }
>
> tmplen = sizeof(path);
> if (sysctl(mib, miblen, path, (size_t *)&tmplen, NULL, 0) == 0)
> printf("%s : %zd\n", path, tmplen);
>
> prints:
> : 1
> : 1
> 8 21
> /usr/local : 11
>
> Thanks,
> Guy Yur
>
This is a separate (valid) problem, but not directly related to
Scott's work here. sysctlbyname now goes directly to the kernel with
no chance for the user.* sysctls to intercept. That should
independently be fixed to maintain the illusion that they're real
sysctl's.
Thanks,
Kyle Evans
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