Hello, John. You wrote 10 апреля 2013 г., 0:58:22: >> Problem is, that every uart device now is independent from each >> other in good "OOP" style, and it looks like interrupt sharing we >> need one interrupt handler per irq (not per device), which will now >> about several UARTs. Something like "multiport" device, bot not >> exactly. JB> No, the interrupt code itself will handle shared interrupts (it will JB> call all handlers). I think in practice that uart is setting And what will happen, if there is two UARTs asserting interrupt in same time? First one returns "FILTER_HANDLED", will second handler be called?
ISA interrupt sharing IS NOT so simple. sio contains a lot of obscure code to work. JB> INTR_EXCL or some such and/or uart doesn't set RF_SHAREABLE when JB> allocating the IRQ. It is probably the latter. You could try just JB> adding RF_SHAREABLE to the bus_alloc_resource_any() for the IRQ to JB> uart and see if that fixes it. sc->sc_ires = bus_alloc_resource_any(dev, SYS_RES_IRQ, &sc->sc_irid, RF_ACTIVE | RF_SHAREABLE); It is here. -- // Black Lion AKA Lev Serebryakov <l...@freebsd.org> _______________________________________________ freebsd-current@freebsd.org mailing list http://lists.freebsd.org/mailman/listinfo/freebsd-current To unsubscribe, send any mail to "freebsd-current-unsubscr...@freebsd.org"