I'm curious how the capturer is created in the case of anonymous functions. I
know the function needs to create a capturer when nested functions are declared
but what happens if there is an anonymous function which is declared in the
code section?
I think the compiler will only know about the requirement to create a capturer
at this point but local variables have already been assigned so do they need to
do an extra copy to the capturer when it's created?
With nested function this is not a problem since the capturer can be created
before any locals are assigned and thus not copying is needed, if I understand
correctly.
======================================
var
gProc: reference to procedure;
procedure DoThis;
var
a: array[0..2] of integer;
begin
// Compiler does not yet know the function requires a capturer
a := [1,2,3];
// DoThis requires a capturer now since the function reference is assigned to
an anonymous (nested) function.
// Does it copy the array (and other local variables) or does the compiler
always make a capturer for all functions if the "anonymousfunctions" mode
switch is enabled?
gProc := procedure
begin
writeln(Length(a));
end;
end;
Regards,
Ryan Joseph
_______________________________________________
fpc-pascal maillist - [email protected]
https://lists.freepascal.org/cgi-bin/mailman/listinfo/fpc-pascal
