> On Feb 16, 2022, at 2:46 AM, Sven Barth via fpc-pascal
> <[email protected]> wrote:
>
> // nested function/procedure/routine variable
> type
> TFoobarNested = function: LongInt is nested;
>
> var
> f: TFoobarFuncRef;
> begin
> // anonymous function/procedure/routine
> f := function: LongInt
> begin
> end;
> end;
"However assigning a nested function variable to a function reference is much
harder.
Assigning a function reference to a nested function variable is hard as well. "
This means if you expanded your example with:
var
n: TFoobarNested;
begin
f := n;
THAT would be hard? I've never passed around nested function vars before so I
don't really know the limitations of this. The important thing is the primary
use case works.
Regards,
Ryan Joseph
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