On Tue, Oct 04, 2016 at 12:31:49PM +0300, Alper Odabaş wrote:
> Dear forum,
>
> By linear algebra, the choice of an (ordered) basis for a free module of
> finite rank m yields an isomorphism to Z^{1 x m}, the module whose entries
> are row matrices with m columns.
>
> In GAP, how to get matrices from the group algebra
> GroupRing(GF(2),CyclicGroup(3))
M:=IdentityMat(3,GF(2));
Cheers,
Bill.
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