Moshtagh:
The presentation for the group Z_9 semi Z_3 is
a^9=b^3=a^b*a^-4=1;
More generally this class of groups [ C_(p^2}] Semi C_p
is
a^(p^2}=b^p=a^b*a^(-p-1) =1
Is this sufficient or did you need a permutation representation?
Walter Becker
> Date: Sat, 9 Jun 2012 15:50:19 +0430
> From: [email protected]
> To: [email protected]
> Subject: Re: [GAP Forum] semidirect products
>
> Dear Forum,
>
> How to construct a group semidirect product of $Z_3$ and $Z_9$ where $Z_i$
> is a cyclic group of order $i$.
> I nead the permutation representation of this group.
>
> Best,
> Moshtagh
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