> ...but I am not able to see an instance of fluidsynth being created in my
processes.
Why should you see it? You are not executing the fluidsynth executable. You
are executing your own program which uses fluidsynth's API, i.e.
libfluidsynth.dylib gets linked to build/exec during compilation. When
executing exec, libfluidsynth.dylib gets loaded and exec becomes your
"fluidsynth" instance. From my understanding you just want to execute
fluidsynth from a C program, which should be possible by doing something
like:
char const * parmList[] = {"-a", "jack", NULL};
execv("/path/to/fluidsynth", parmList);
Tom
2017-03-26 8:00 GMT+02:00 Anuj Deshpande <a...@makerville.io>:
> Hi
>
> I am trying to create a new instance of fluidsynth from a C program -
>
>
> #include "../fluidsynth-1.1.6/include/fluidsynth.h"
>
> void fs_init(){
>
> printf("### Begin fs_init ### \r\n");
> fluid_settings_t* settings;
> fluid_synth_t* synth;
> fluid_audio_driver_t* adriver;
> settings = new_fluid_settings();
>
> /* Set the synthesizer settings, if necessary */
> printf("Creating new synth .. \r\n");
> synth = new_fluid_synth(settings);
> printf("Creating new audio driver.. \r\n");
> fluid_settings_setstr(settings, "audio.driver", "coreaudio");
> adriver = new_fluid_audio_driver(settings, synth);
>
> }
>
> My build instruction looks like -
>
>
> $(CC) -o build/exec -g -Wall src/main.c /usr/local/lib/libfluidsynth.dylib -lm
>
> The program builds fine, but I am not able to see an instance of
> fluidsynth being created in my processes.
>
>
> What would be the correct way to invoke fluidsynth from within another
> program? Is there a sample code/project available?
>
> -Anuj
>
>
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>
>
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