On 23.07.2017, at 12:20, Nicolas George <[email protected]> wrote:
>
>> + if (!q->last_pkt) {
>> + q->first_pkt = pkt1;
>> + } else {
>> + q->last_pkt->next = pkt1;
>> + }
If kept, I would invert the condition, otherwise the else is essentially a
double-negation.
>> + q->last_pkt = pkt1;
>
> There is a little known but nice simplification when implementing
> linked-lists like that: instead of "last_pkt", have in the structure
> "AVPacketList **tail", and you can write this whole block without a
> condition:
>
> *q->tail = pkt1;
> q->tail = &(*q->tail)->next;
It's without condition and an optimization, I am not sure it quite qualifies as
"simplification" though.
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