And to add on to Rich Ulrich's note, if the mean isn't zero, then z^2
is non-central chi-square.
-Dick Startz
On Thu, 29 Nov 2001 12:29:47 -0500, Rich Ulrich <[EMAIL PROTECTED]>
wrote:
>On Thu, 29 Nov 2001 15:48:48 +0300, Ludovic Duponchel
><[EMAIL PROTECTED]> wrote:
>
>> If x values have a normal distribution, is there a normal distribution
>> for x^2 ?
>
>If z is standard normal [ that is, mean 0, variance 1.0 ]
>then z^2 is chi squared with 1 degree of freedom.
>
>And the sum of S independent z variates
>is chi squared with S degrees of freedom.
----------------------
Richard Startz [EMAIL PROTECTED]
Lundberg Startz Associates
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