if bids is ordered by index then you could just return BID.objects.filter(...).filter(pk__lte=id).count() and that should be what your after in one step (if I've understood the question correctly).
-- G On Mar 7, 7:10 am, Hasan Karahan <[email protected]> wrote: > Hi, > > I'm wondering if there is an efficient way to look-up the index of a given > object in a query-set? I'm using now the following approach: > > def get_index (id): > > bids = BID.objects.filter (..) > obj2idx = dict (zip (bids, xrange (bids.count ())) > > bid = BID.objects.get (id=ID) > > return obj2idx (bid) > > This has a linear time processing.. is there a more efficient way to do it? -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
