All right, I think I've got it:
1: I tried to use InlineModelAdmin with a ManyToMany-Field.
You can do this, but you've got to do it as described here I guess:
http://docs.djangoproject.com/en/dev/ref/contrib/admin/#working-with-many-to-many-intermediary-models
.
2: I confused the model which has the foreign key with the other one.
If class a has a foreign key to class b, it's class a which inherits
from TabularInline, not the other way around like I did.
3: You don't have to register Inline classes, as Karen said in her
mail (which I got while I'm writing this one...Thanks Karen!)
Here's the working example:
from django.db import models
class a(models.Model):
title = models.CharField(max_length=50)
def __unicode__(self):
return self.title
class b(models.Model):
title = models.CharField(max_length=50)
other_model = models.ForeignKey('a')
def __unicode__(self):
return self.title
admin.py:
from myproject.myapp.models import a, b
from django.contrib import admin
class bInline(admin.TabularInline):
model = b
class aAdmin(admin.ModelAdmin):
inlines = [bInline]
admin.site.register(a, aAdmin)
Thanks!
Benjamin
Am 21.01.2009 um 17:36 schrieb Benjamin Buch:
> I simplified the models a bit for better demonstration.
> Here's the model:
>
> from django.db import models
>
> class a(models.Model):
> title = models.CharField(max_length=50)
> other_model = models.ManyToManyField('b')
>
> def __unicode__(self):
> return self.title
>
> class b(models.Model):
> title = models.CharField(max_length=50)
>
> def __unicode__(self):
> return self.title
>
> Here's admin.py:
>
> from myproject.myapp.models import a, b
> from django.contrib import admin
>
> class bInline(admin.TabularInline):
> model = b
>
> class aAdmin(admin.ModelAdmin):
> inlines = [bInline]
>
> admin.site.register(b, bInline)
> admin.site.register(a, aAdmin)
>
> Now, when I'm trying to acess the admin in the browser, I get this
> error thrown (Traceback):
>
> Traceback:
> File "/Library/Python/2.5/site-packages/django/core/handlers/
> base.py" in get_response
> 77. request.path_info)
> File "/Library/Python/2.5/site-packages/django/core/urlresolvers.py"
> in resolve
> 181. for pattern in self.url_patterns:
> File "/Library/Python/2.5/site-packages/django/core/urlresolvers.py"
> in _get_url_patterns
> 205. patterns = getattr(self.urlconf_module,
> "urlpatterns", self.urlconf_module)
> File "/Library/Python/2.5/site-packages/django/core/urlresolvers.py"
> in _get_urlconf_module
> 200. self._urlconf_module =
> __import__(self.urlconf_name, {}, {}, [''])
> File "/Users/benjamin/Code/django/myproject/../myproject/urls.py" in
> <module>
> 6. admin.autodiscover()
> File "/Library/Python/2.5/site-packages/django/contrib/admin/
> __init__.py" in autodiscover
> 54. __import__("%s.admin" % app)
> File "/Users/benjamin/Code/django/myproject/../myproject/myapp/
> admin.py" in <module>
> 10. admin.site.register(b, bInline)
> File "/Library/Python/2.5/site-packages/django/contrib/admin/
> sites.py" in register
> 76. validate(admin_class, model)
> File "/Library/Python/2.5/site-packages/django/contrib/admin/
> validation.py" in validate
> 72. if cls.date_hierarchy:
>
> Exception Type: AttributeError at /admin/
> Exception Value: type object 'bInline' has no attribute
> 'date_hierarchy'
>
> Thanks,
> Benjamin
>
> Am 21.01.2009 um 17:19 schrieb Karen Tracey:
>
>> On Wed, Jan 21, 2009 at 10:53 AM, Benjamin Buch <[email protected]>
>> wrote:
>>
>> Hi,
>>
>> I'm trying to use InlineModelAdmins, but get a strange error
>> thrown...
>>
>> You get this error raised when you do what, exactly? Also the full
>> traceback might provide a clue of what is going on.
>>
>> Karen
>
> >
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