Hi,
i hope any one can help me.
I want to generate a rss-feed.
The url ist http://localhost:8000/isf/info/.
All works fine but the title of an Item and the Description are still
the same!
How can i change the title of an feed item in the feed to the title
from the model
and the description of the feed item to the description from the
model.
I get only the String from the __unicode__(self): Method. An this
string represent
the title and the description, why ?
Please help me!
My urls.py config:
feeds = {
'rss': Rss2Feed,
}
urlpatterns = patterns('django.contrib.syndication.views',
url(r'^(?P<url>.*)/$', 'feed', {'feed_dict': feeds},
name="fh_feeds",),
)
Thats my models.py class:
class Item(models.Model):
title = models.CharField(max_length=30)
banner = models.CharField(max_length=30, null=True)
description = models.TextField(null=True)
pub_date = models.DateTimeField(auto_now=True,
verbose_name="Public Date")
expire_date = models.DateTimeField(verbose_name="Expire Date")
author = models.ForeignKey(User, editable=False)
def authors_email(self):
return "%s"%(self.author.email)
def get_absolute_url(self):
return "%s/"%(self.id)
def __unicode__(self):
return self.title
class Meta:
ordering = ['-pub_date']
class Item_Category(models.Model):
item = models.ForeignKey(Item)
category = models.ForeignKey(Category)
def __unicode__(self):
return "%s"%self.item.id
And thats my feed.py class:
class Rss2Feed(Feed):
#thats my hard-coded title,link and description for my info feed
title = "Info"
link = "/info/"
description = "Info-Site"
# i want to show all items of my model with the slug info
def items(self):
listOfItems = []
itemToCategoryForInfo =
Item_Category.objects.select_related().filter(category__slug = "info")
for selectedItem in itemToCategoryForInfo:
listOfItems.append(selectedItem.item)
return listOfItems
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