I'm now turned to using the workaround of extracting the block I want
to reuse to an additional file, and include every time I need it
(which is always on the same template inheritance line). This feels
like cheating though. It would be a lot cleaner if I could just
reference the base template's block, but I'm not finding any
documentation on this matter :\
Is there any alternative (cleaner) way to accomplish the same?
Cheers,
Filipe
On Apr 23, 7:35 pm, Filipe Correia <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I'm wondering if the following is possible with django templates. I
> would like to override a given parent block, while maintaining the
> contents of it's child block:
>
> base.html:
> {% block firstblock %}
> <div>
> Bla bla bla
> {% block secondblock %} ble ble ble {% endblock %}
> </div>
> {% endblock %}
>
> inherited.html:
> {% extends "base.html" %}
> {% block firstblock %}
> <div>
> this is being overriden
> {% block secondblock %} {{ block.super }} {% endblock %}
> </div>
> {% endblock %}
>
> I have a case similar with this one, which is not working as I thought
> it would ( {{ block.super }} is outputting nothing, instead of the
> value from the parent template). Might I be doing something wrong or
> is this the expected behavior?
>
> thanks,
> Filipe Correia
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en
-~----------~----~----~----~------~----~------~--~---
