Tim Chase wrote: >> How can I retrieve all objects that are *not* in that list? >> >> Something like "Model.objects.filter(id__not_in = processed_ids)". >> Unlike filter(id__in=...) which works just fine the __not_in modifier >> apparently isn't understood by django. > > > As commented recently on the list, you want "filter()"'s evil > twin "exclude()": > > exclude(id_in=...)
That's it. Thanks. Now with the above example if I don't have a list of IDs but a list of the processed objects I'm not able to pass these as an argument to the __in operator. This: Model.objects.filter(...).exclude(id__in = processed) gives me: Truncated incorrect DOUBLE value: 'Model object' I have to use id__in=[p.id for p in processed] instead. Am I doing something wrong again or is it expected behaviour? Thanks Michal --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users?hl=en -~----------~----~----~----~------~----~------~--~---
