On Fri, Feb 11, 2011 at 4:06 PM, kyleduncan <[email protected]> wrote:
> I dont understand what the x is, but thank you so much for fixing this
> for me in a matter of minutes!
>
You're welcome.
The 'key' kwarg to the sort function expects a value. Instead of
giving it a single value, you can pass a function.
So, you could have done this:
def return_last_login(record):
return record.user.last_login
Then: my_list.sort(key = return_last_login(x))
But you can use a shortcut and use the 'lambda' keyword, which just
returns an anonymous function.
So, these two are equivalent:
my_function = return_last_login
my_function = lambda x: x.user.last_login
I hope this helps.
Shawn
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