Will operator fusion in Relax perform the following fusion? Let me illustrate
it with a diagram.
```bash
Merge different branch with same starting op.
|---> B --> D ...
A --->
|---> C --> E ...
The B and C have same call.op, call.args, call.attr, can be merged as:
|---> D ...
A ---> B --->
|---> E ...
```
I think this is a very classic fusion pattern, yet it wasn’t fused in my
subgraph, which puzzles me. Or perhaps this fusion is handled in a specific
pass that I didn’t invoke?
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