On 21.09.23 16:52, Kinsey Moore wrote:
On Thu, Sep 21, 2023 at 9:47 AM Sebastian Huber <sebastian.hu...@embedded-brains.de <mailto:sebastian.hu...@embedded-brains.de>> wrote:

    On 20.09.23 20:35, Kinsey Moore wrote:
    [...]
     > @@ -1306,8 +1307,22 @@ static void process_delayed_work(void)
     >       while (!rtems_chain_is_tail(&process_work_chain, node)) {
     >               work = (struct delayed_work*) node;
     >               rtems_chain_node* next_node = rtems_chain_next(node);
     > +
     > +             /*
     > +              * Don't leave extracted node exposed to other
    operations
     > +              * under RTEMS_DEBUG
     > +              */
     > +#ifdef RTEMS_DEBUG
     > +             mutex_lock(&delayed_work_mutex);
     > +#endif
     >               rtems_chain_extract(node);
     > +#ifdef RTEMS_DEBUG
     > +             node->next = node;
     > +             mutex_unlock(&delayed_work_mutex);
     > +#endif
     > +
     >               work->callback(&work->work);
     > +             rtems_chain_set_off_chain(node);
     >               node = next_node;
     >       }
     >   }

    This change makes no sense to me. The code should work regardless if
    RTEMS_DEBUG is defined or not.


RTEMS_DEBUG introduces a behavioral change in rtems_chain_extract() such that extracted nodes are automatically set off-chain. When RTEMS_DEBUG is not set, node->next is left untouched. This has to be managed because this code needs the node to remain on-chain so that it is not re-queued during the operation.

Yes, but while a node is on a chain you must not call rtems_chain_set_off_chain(). If you want to use the off-chain state, then you have to use this:

rtems_chain_extract(node);
rtems_chain_set_off_chain(node);

or

rtems_chain_extract_unprotected(node);
rtems_chain_set_off_chain(node);

The automatic set off-chain in RTEMS_DEBUG is just to ensure that basic chain operations are used in the right state.

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