Hi @comaniac, 

May I ask how the graph ends up with a `nn.conv2d + nn.relu + nn.conv2d + 
nn.relu` ? Is the graph going through a BYOC kind of partitioning (sorry if the 
question is naive)?

As for S1 vs S2, could we do both? Use an heuristic like "ignore the task 
without any call node" and then let the task scheduler judge if it needs to 
spend time on the task?

Thanks





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